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Inequalities

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These are the solutions to the NSSCO past questions on Inequalities.
The TI-84 Plus CE shall be used for applicable questions.
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Notes and Rules

(1.) At least 5 means ≥ 5
It means that the minimum should be 5

(2.) At most 5 means ≤ 5
It means that the maximum should be 5

(3.) Just 5 means = 5
It means exactly 5 or equal to 5

(4.) More than 5 means > 5

(5.) Less than 5 means < 5

(6.) No more than 5 means ≤ 5
It should not be more than 5
It means 5 or less

(7.) No less than 5 means ≥ 5
It should not be less than 5
It means 5 or more

Rules of Inequalities
c, d, e are real numbers

$ (1.)\text{ If } c \lt d \text{ and } d \lt e, \text{ then } c \lt e \quad\dots\text{Transitive Rule} \\[3ex] (2.)\text{ If } c \gt d \text{ and } d \gt e, \text{ then } c \gt e \quad\dots\text{Transitive Rule} \\[3ex] (3.)\text{ If } c \lt d, \text{ then } d \gt c \\[3ex] (4.)\text{ If } c \gt d, \text{ then } d \lt c \\[3ex] (5.)\text{ If } c \lt d, \text{ then } -c \gt -d \\[3ex] (6.)\text{ If } c \gt d, \text{ then } -c \lt -d \\[3ex] (7.)\text{ If } c \lt d, \text{ then } \dfrac{1}{c} \gt \dfrac{1}{d} \\[5ex] (8.)\text{ If } c \gt d, \text{ then } \dfrac{1}{c} \lt \dfrac{1}{d} \\[5ex] (9.)\text{ If } c \lt d, \text{ then } (c + e) \lt (d + e) \\[3ex] (10.)\text{ If } c \gt d, \text{ then } (c + e) \gt (d + e) \\[3ex] (11.)\text{ If } c \lt d, \text{ then } (c - e) \lt (d - e) \\[3ex] (12.)\text{ If } c \gt d, \text{ then } (c - e) \gt (d - e) \\[3ex] (13.)\text{ If } c \lt d, \text{ and } e \gt 0; \text{ then } ce \lt de \\[3ex] (14.)\text{ If } c \lt d, \text{ and } e \lt 0; \text{ then } ce \gt de \\[3ex] (15.)\text{ If } c \gt d, \text{ and } e \gt 0; \text{ then } ce \gt de \\[3ex] (16.)\text{ If } c \gt d, \text{ and } e \lt 0; \text{ then } ce \lt de \\[3ex] (17.)\text{ If } c \lt d, \text{ and } e \gt 0; \text{ then } \dfrac{c}{e} \lt \dfrac{d}{e} \\[5ex] (18.)\text{ If } c \gt d, \text{ and } e \gt 0; \text{ then } \dfrac{c}{e} \gt \dfrac{d}{e} \\[5ex] (19.)\text{ If } c \lt d, \text{ and } e \lt 0; \text{ then } \dfrac{c}{e} \gt \dfrac{d}{e} \\[5ex] (20.)\text{ If } c \gt d, \text{ and } e \lt 0; \text{ then } \dfrac{c}{e} \lt \dfrac{d}{e} $

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(2.) Solve the inequality $8(2 - 3x) - 4(1 - 2x) \le 0$


$ 8(2 - 3x) - 4(1 - 2x) \le 0 \\[3ex] 16 - 24x - 4 + 8x \le 0 \\[3ex] -16x + 12 \le 0 \\[3ex] -16x \le 0 - 12 \\[3ex] -16x \le -12 \\[3ex] x \ge \dfrac{-12}{-16} \\[5ex] \quad\dots\text{inequality is reversed...division by a negative value} \\[5ex] x \ge \dfrac{3}{4} $
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