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Bahamas General Certificate of Secondary Education: Mathematics: Paper 1

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These are the solutions to the BGCSE Mathematics Paper 1 questions.
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Ministry of Education National Examinations
Bahamas General Certificate of Secondary Education
Mathematics
Paper 1 (Core/Extended)

Time: 1:00 pm – 2:30 pm

Instructions to Candidates
(1.) Do not open this booklet until you are told to do so.
(2.) Write your School Number, Candidate Number, Surname and Initials in the spaces provided at the top of this page.
(3.) Answer ALL questions in the spaces provided for each question.
(4.) Omission of essential working will result in loss of marks.
(5.) ALL working must be shown.
(6.) ALL working must be done in blue or black ink, except for drawings, lines and constructions which may be done in pencil.

Information for Candidates
(1.) Calculators (Not Graphing Calculators) may be used.
(2.) Tracing paper may be used.
(3.) Geometrical instruments are required.
(4.) The mark for each question, or part question, is shown in brackets [ ].
(5.) The total number of marks for this paper is 100.

Formula Sheet: Information and Formulae
(1.) Sequences: A number pattern is shown below.

Number 1

(a.) Write the missing row from the number pattern in the box above.
(b.) Find the sum of the 10th row.


(a.) Let us fix the typo in the question, and write the answer to (a.).

Number 1

$ (b.) \quad\text{10th row} \\[3ex] 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 \\[3ex] \text{Sum} = 21 + 7 + 8 + 9 + 10 \\[3ex] = 55 $
(2.) Numbers: Write the following ratios in their simplest form:

$ (a.)\;\; 144 : 360 \\[3ex] (b.)\;\; \dfrac{7}{8} : \dfrac{11}{4} \\[5ex] (c.)\;\; 68g : 1.9kg \\[3ex] $

$ (a.) \\[3ex] 144 : 360 \\[3ex] = \dfrac{144}{360} \\[5ex] = \dfrac{144 \div 36}{360 \div 36} \\[5ex] = \dfrac{4 \div 2}{10 \div 2} \\[5ex] = \dfrac{2}{5} \\[5ex] = 2 : 5 \\[5ex] (b.) \\[3ex] \dfrac{7}{8} : \dfrac{11}{4} \\[5ex] = \dfrac{7}{8} \div \dfrac{11}{4} \\[5ex] = \dfrac{7}{8} \times \dfrac{4}{11} \\[5ex] = \dfrac{7 \times 1}{2 \times 11} \\[5ex] = \dfrac{7}{22} \\[5ex] = 7 : 22 \\[5ex] (c.) \\[3ex] 68g : 1.9kg \\[3ex] ............................................... \\[3ex] 1.9kg \;\;to\;\; g \\[3ex] \text{Set up units:} \\[3ex] 1.9kg \times \dfrac{...g}{...kg} \\[5ex] \text{Set up measurements and units:} \\[3ex] 1.9kg \times \dfrac{10^3\;g}{1\;kg} \\[5ex] = 1.9 \times 1000g \\[3ex] = 1900g \\[3ex] ............................................... \\[3ex] = \dfrac{68g}{1900g} \\[5ex] = \dfrac{68 \div 4}{1900 \div 4} \\[5ex] = \dfrac{17}{475} \\[5ex] = 17 : 475 $
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